What is the output of the following piece of code? #mod1 def change(a): b=[x*2 for x in a] print(b) #mod2 def change(a): b=[x*x for x in a] print(b) from mod1 import change from mod2 import change #main s=[1,2,3] change(s)

Mr. Dubey • 52.30K Points
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Q. What is the output of the following piece of code?
#mod1
def change(a):
b=[x*2 for x in a]
print(b)
#mod2
def change(a):
b=[x*x for x in a]
print(b)
from mod1 import change
from mod2 import change
#main
s=[1,2,3]
change(s)

(A) [2,4,6].

(B) [1,4,9].

(D) There is a name clash

Correct : Option (D)

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Q. What is the output of the following piece of code? #mod1 def change(a): b=[x*2 for x in a] print(b) #mod2 def change(a): b=[x*x for x in a] print(b) from mod1 import change from mod2 import change #main s=[1,2,3] change(s)

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Q. What is the output of the following piece of code? #mod1 def change(a): b=[x2 for x in a] print(b) #mod2 def change(a): b=[xx for x in a] print(b) from mod1 import change from mod2 import change #main s=[1,2,3] change(s)