What is the output of the following C++ code?

Dharmendra Sir • 3.53K Points
Extraordinary

Q. What is the output of the following C++ code?

Code:

#include<iostream> 
using namespace std; 
  
class MyClass
{ 
  public: 
    MyClass(); 
}; 
  
MyClass::MyClass()  { 
    cout << "Constructor is called\n"; 
} 
  
int main() 
{ 
    cout << " Before \n"; 
    MyClass myclass(); 
    cout << " After \n"; 
    return 0; 
}

(A) Before Constructor is called After
(B) Before After
(C) Constructor is called Before After
(D) None of the above.

Correct Answer - Option(B)
Views: 103
Filed under category C++

Explanation by: Dharmendra Sir

Note that the line “MyClass maclass();” is not a constructor call. The compiler considers this line as a function declaration that receives no parameters and returns an object of type MyClass.

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