18 years ago, a man was three times as old as his son. Now, the man is twice as old as his son. The sum of the present ages of the man and his son is = ?

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Tutor III Math

Q. 18 years ago, a man was three times as old as his son. Now, the man is twice as old as his son. The sum of the present ages of the man and his son is = ?

(A) 54 years

(B) 72 years

(D) 108 years

Correct Answer - Option(D)

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