D

Dhruva • 4.38K Points
Extraordinary Math 

Q. The smallest number, which when increased by 5 is divisible by each of 24, 32, 36 and 64 is ?

  • (A) 869
  • (B) 859
  • (C) 571
  • (D) 427
Correct Answer - Option(C)
Explanation by: Dhruva 
LCM of (24, 32, 36, 64)
⇒ 8 × 3 × 4 × 3 × 2 = 576
Required number is 576 - 5 = 571

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