Q. When 335 is added to 5A7, the result is 8B2. 8B2 is divisible by 3. What is the largest possible value of A ?
5A7 + 335 = 8B2 ⇒ A → 1, 2, 3, 4, 5 & B → 5, 6, 7, 8,9 8B2 is exactly divisible by 3. ∴ 8 + B + 2 = multiple of 3 ∴ B = 5 or 8 ⇒ A = 1 or 4
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