V

Vaibhav Shukla • 4.53K Points
Extraordinary Reasoning

  • (A) 1247
  • (B) 4847
  • (C) 5247
  • (D) 5847
Correct Answer - Option(D)

Explanation by: Vaibhav Shukla
R is in every group of letter and 4 is in every group of numbers so R = 4 C L E A R = 5 6 7 8 4 , S P A R E = 9 0 8 4 7 Here 847 are common So CL = 56 and SP = 90 Thus C A R E = 8 4 7 

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