K

Kirti • 10.45K Points
Tutor II Math 

Q. A father was 12 times as old as his son 20 years back. Now he is twice as old as his son. What are their present ages?

  • (A) Father 44 and son 22
  • (B) Father 55 and son 33
  • (C) Father 66 and son 44
  • (D) None of these
Correct Answer - Option(A)
Explanation by: Kirti 
Suppose the present age of son = P years
The present age of father = 2P years
According to question ,
20 years ago , (2P – 20) = 12 (P – 20)
⇒ 2P – 20 = 12P – 240
⇒ 12P – 2P = 240 – 20
⇒ 10P = 220
∴ P = 22 years
Age of father = 2P = 2 x 22 = 44 years

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