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Q. In finding the HCF of two numbers by division method, the last divisor is 18 and quotients are 2, 7 and 3. Find the numbers.
Here , Last divisor = 18 and quotient = 3 ∴ Dividend = 18 × 3 = 54 Now, divisor = 54, quotient = 7 and remainder = 18 ∴ Dividend = 7 × 54 + 18 = 378 + 18 = 396 Now, divisor = 396, quotient = 2 and remainder = 54 ∴ Dividend = 2 × 396 + 54 = 792 + 54 = 846 Hence, the required numbers are 396 and 846.
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