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Jatin Dubey • 3.72K Points
Extraordinary Math
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(A) RS.16596.88
(B) RS.16789.08
(C) RS.17630.77
(D) RS.17389.12
Correct Answer - Option(D)
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Explanation by: Umar Hassan
Given, P = ₹ 15000, R = 12 %
and n = 11/4 = 5/4 Yr
According to the formula,
Amount = p [1 + R/(100 x 4)]^4n
= 15000 x [1 + 12/(100 x 4)]^(4 x 5/4)
= 15000(412/400)^5
= 15000 (103/100)^5
= 15000 x (103/100) x (103/100) x (103/100) x (103/100) x (103/100)
= (15 x 103 x 103 x 103 x 103 x 103) / 10000000
= ₹ 17389.111
= ₹ 17389.12 (approx )

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