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Dear candidates you will find MCQ questions of Hydraulics here. Learn these questions and prepare yourself for coming examinations and interviews. You can check the right answer of any question by clicking on any option or by clicking view answer button.

M

Mr. Dubey • 51.32K Points
Coach

Q. 141) Determine the head over sill of a 90° V-notch when the discharge passing over it is 100 lit/sec. consider Cd 0.6.

(A) 0.346 cm
(B) 3.46 cm
(C) 0.346 m
(D) 3.46 m
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Mr. Dubey • 51.32K Points
Coach

Q. 142) A 12 m long weir is subdivided by four intermediate vertical posts each 0.6 m wide. If the weir is discharging under a head of 0.5 m, calculate discharge using Francis formula.

(A) 5.895 m3/sec
(B) 5.895 m3/hr
(C) 5.895 lit/sec
(D) 5.895 lit/ hr
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Mr. Dubey • 51.32K Points
Coach

Q. 143) As the flow moves in the pipe, fluid pressure decreases.

(A) true
(B) false
(C) all
(D) none
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Mr. Dubey • 51.32K Points
Coach

Q. 144) The velocity of liquid particles at the centre of pipe is less than the velocity of particles near the inner surface of pipe.

(A) true
(B) false
(C) all
(D) none
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Mr. Dubey • 51.32K Points
Coach

Q. 145) The frictional resistance is proportional to the velocity in laminar flow

(A) true
(B) false
(C) all
(D) none
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Mr. Dubey • 51.32K Points
Coach

Q. 146) The fR depends on the nature of the surface of contact in laminar flow.

(A) true
(B) false
(C) all
(D) none
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Mr. Dubey • 51.32K Points
Coach

Q. 147) Head loss due to entry.

(A) h = 0.5 V12/2g
(B) h = 0.5 V22/2g
(C) h = (V2 – V3)2/2g
(D) h = 0.5 V32/2g
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Mr. Dubey • 51.32K Points
Coach

Q. 148) Head loss due to exist.

(A) h = 0.5 V12/2g
(B) h = 0.5 V22/2g
(C) h = (V2 – V3)2/2g
(D) h = 0.5 V32/2g
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Mr. Dubey • 51.32K Points
Coach

Q. 149) Head loss due to sudden contraction.

(A) h = 0.5 V12/2g
(B) h = 0.5 V22/2g
(C) h = (V2 – V3)2/2g
(D) h = 0.5 V32/2g
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M

Mr. Dubey • 51.32K Points
Coach

Q. 150) Head loss due to sudden enlargement.

(A) h = 0.5 V12/2g
(B) h = 0.5 V22/2g
(C) h = (V2 – V3)2/2g
(D) h = 0.5 V32/2g
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